cat <<'X'
 long long bnum=-1,bden=1@
 int ma=ba, mb=bb@
 long long aa=(int)nn[ma], bb2=(int)nn[mb]@
 long long b4=bb2*bb2*bb2*bb2@
 long long den=aa*aa*b4@
 long long p1=(long long)d[ma]*b4@
 long long p2=(long long)d[mb]*d[mb]*aa*aa@
 long long num@
 if(p1 > p2) num=p1-p2@ else num=p2-p1@
 bnum=num@ bden=den@
 double T=best+1e-6@
 if(T > 0) {} else T=1e-6@
 printf("phase2 T %.17g exact %lld/%lld\n",T,bnum,bden)@
 int j=0@
 int i@
 for(i=0@i!=M@++i){
  while(j!=M && (A[i].v-T) > B[j].v) ++j@
  int k=j@
  while(k!=M && !(B[k].v > A[i].v+T)){
   int ma2=A[i].id, mb2=B[k].id@
   if(ma2!=mb2 && ((ma2&mb2)==mb2)){
    long long aa2=(int)nn[ma2], bb3=(int)nn[mb2]@
    long long b42=bb3*bb3*bb3*bb3@
    long long den2=aa2*aa2*b42@
    long long q1=(long long)d[ma2]*b42@
    long long q2=(long long)d[mb2]*d[mb2]*aa2*aa2@
    long long num2@
    if(q1 > q2) num2=q1-q2@ else num2=q2-q1@
    if(bnum==-1 || bnum*den2 > num2*bden){
     bnum=num2@ bden=den2@ bb=mb2@ ba=ma2@
    } else if(bnum*den2 == num2*bden){
     if(lexless(mb2,bb)){ bb=mb2@ ba=ma2@ }
    }
   }
   ++k@
  }
 }
X